What is x^2+(y-5)^2=9 ?

The solution to x^2+(y-5)^2=9 is Circle with (a,b)=(0,5),r=3

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x^2+(y-5)^2=9

x^{2} + (y - 5)^{2} = 9

(a, b) = (0, 5), r = 3

Solution steps

x^{2} + (y - 5)^{2} = 9

Rewrite

x^{2} + (y - 5)^{2} = 9

in the form of the standard circle equation

(x - 0)^{2} + (y - 5)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (0, 5), r = 3

x^{2} + 8 y = - y^{2} + 6 x

x^{2} + y^{2} + 4 x - 10 y = 4

(- x + 3)^{2} + (- y + 2)^{2} = 2^{2}

x^{2} + y^{2} - x - 4 y + 4 = 0

p^{2} + q^{2} = 170

What is x^2+(y-5)^2=9 ?
The solution to x^2+(y-5)^2=9 is Circle with (a,b)=(0,5),r=3