What is (-x+3)^2+(-y+2)^2=2^2 ?

The solution to (-x+3)^2+(-y+2)^2=2^2 is Circle with (a,b)=(3,2),r=2

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(-x+3)^2+(-y+2)^2=2^2

(- x + 3)^{2} + (- y + 2)^{2} = 2^{2}

(a, b) = (3, 2), r = 2

Solution steps

(- x + 3)^{2} + (- y + 2)^{2} = 2^{2}

Rewrite

(- x + 3)^{2} + (- y + 2)^{2} = 2^{2}

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 2

x^{2} + y^{2} - x - 4 y + 4 = 0

p^{2} + q^{2} = 170

x^{2} + y^{2} - 8 x - 2 y + 11 = 0

(x + 4)^{2} + (y - 1)^{2} = 8

x^{2} + y^{2} - 12 x + 8 y - 60 = 0

What is (-x+3)^2+(-y+2)^2=2^2 ?
The solution to (-x+3)^2+(-y+2)^2=2^2 is Circle with (a,b)=(3,2),r=2