What is 3x^2-6x+3y^2-18y-78=0 ?

The solution to 3x^2-6x+3y^2-18y-78=0 is Circle with (a,b)=(1,3),r=6

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3x^2-6x+3y^2-18y-78=0

3 x^{2} - 6 x + 3 y^{2} - 18 y - 78 = 0

(a, b) = (1, 3), r = 6

Solution steps

3 x^{2} - 6 x + 3 y^{2} - 18 y - 78 = 0

Rewrite

3 x^{2} - 6 x + 3 y^{2} - 18 y - 78 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 3)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (1, 3), r = 6

x^{2} + y^{2} = 1^{2}

x^{2} + y^{2} = 22

(x - 7)^{2} + (y - 1)^{2} = 25

(x - 1)^{2} + (y - 3)^{2} = 36

(x - 1)^{2} + (y - 3)^{2} = 81

What is 3x^2-6x+3y^2-18y-78=0 ?
The solution to 3x^2-6x+3y^2-18y-78=0 is Circle with (a,b)=(1,3),r=6