What is x^2+y^2=2sqrt(2) ?

The solution to x^2+y^2=2sqrt(2) is Circle with (a,b)=(0,0),r=2^{3/4}

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x^2+y^2=2sqrt(2)

x^{2} + y^{2} = 22

(a, b) = (0, 0), r = 2^{\frac{3}{4}}

Solution steps

x^{2} + y^{2} = 22

Rewrite

x^{2} + y^{2} = 22

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (2^{\frac{3}{4}})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2^{\frac{3}{4}}

(x - 7)^{2} + (y - 1)^{2} = 25

(x - 1)^{2} + (y - 3)^{2} = 36

(x - 1)^{2} + (y - 3)^{2} = 81

(x + 1)^{2} + (y + 1)^{2} = 9

4 (x - 5)^{2} + 4 y^{2} = 20

What is x^2+y^2=2sqrt(2) ?
The solution to x^2+y^2=2sqrt(2) is Circle with (a,b)=(0,0),r=2^{3/4}