What is (x+1)^2+(y+1)^2=9 ?

The solution to (x+1)^2+(y+1)^2=9 is Circle with (a,b)=(-1,-1),r=3

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(x+1)^2+(y+1)^2=9

(x + 1)^{2} + (y + 1)^{2} = 9

(a, b) = (- 1, - 1), r = 3

Solution steps

(x + 1)^{2} + (y + 1)^{2} = 9

Rewrite

(x + 1)^{2} + (y + 1)^{2} = 9

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 1), r = 3

4 (x - 5)^{2} + 4 y^{2} = 20

x^{2} + y^{2} - 3 x + 5 y - 1 = 0

(x - 2)^{2} + (y - 2)^{2} = 8

(x - 2)^{2} + (y - 2)^{2} = 9

(x - 1)^{2} + (y - 3)^{2} = 13

What is (x+1)^2+(y+1)^2=9 ?
The solution to (x+1)^2+(y+1)^2=9 is Circle with (a,b)=(-1,-1),r=3