What is (x-2)^2+(y-2)^2=9 ?

The solution to (x-2)^2+(y-2)^2=9 is Circle with (a,b)=(2,2),r=3

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(x-2)^2+(y-2)^2=9

(x - 2)^{2} + (y - 2)^{2} = 9

(a, b) = (2, 2), r = 3

Solution steps

(x - 2)^{2} + (y - 2)^{2} = 9

Rewrite

(x - 2)^{2} + (y - 2)^{2} = 9

in the form of the standard circle equation

(x - 2)^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, 2), r = 3

(x - 1)^{2} + (y - 3)^{2} = 13

x^{2} + y^{2} + 8 x - 12 y - 8 = 0

(x - 2)^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} + 4 x + 4 y - 1 = 0

x^{2} + y^{2} - 13 = 0

What is (x-2)^2+(y-2)^2=9 ?
The solution to (x-2)^2+(y-2)^2=9 is Circle with (a,b)=(2,2),r=3