What is (x-2)^2+(y+9)^2=39^2 ?

The solution to (x-2)^2+(y+9)^2=39^2 is Circle with (a,b)=(2,-9),r=39

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(x-2)^2+(y+9)^2=39^2

(x - 2)^{2} + (y + 9)^{2} = 3 9^{2}

(a, b) = (2, - 9), r = 39

Solution steps

(x - 2)^{2} + (y + 9)^{2} = 3 9^{2}

Rewrite

(x - 2)^{2} + (y + 9)^{2} = 3 9^{2}

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 9))^{2} = 3 9^{2}

Therefore the circle properties are:

(a, b) = (2, - 9), r = 39

x^{2} + (y + 8)^{2} = 400

x^{2} + y^{2} - 2 x - 10 y + 17 = 0

x^{2} + y^{2} - 2 x + 10 y + 19 = 0

(x - 5)^{2} + (y + 2)^{2} = 25

x^{2} + y^{2} - 6 x - 10 y = 34

What is (x-2)^2+(y+9)^2=39^2 ?
The solution to (x-2)^2+(y+9)^2=39^2 is Circle with (a,b)=(2,-9),r=39