What is x^2+(y+8)^2=400 ?

The solution to x^2+(y+8)^2=400 is Circle with (a,b)=(0,-8),r=20

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x^2+(y+8)^2=400

x^{2} + (y + 8)^{2} = 400

(a, b) = (0, - 8), r = 20

Solution steps

x^{2} + (y + 8)^{2} = 400

Rewrite

x^{2} + (y + 8)^{2} = 400

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 8))^{2} = 2 0^{2}

Therefore the circle properties are:

(a, b) = (0, - 8), r = 20

x^{2} + y^{2} - 2 x - 10 y + 17 = 0

x^{2} + y^{2} - 2 x + 10 y + 19 = 0

(x - 5)^{2} + (y + 2)^{2} = 25

x^{2} + y^{2} - 6 x - 10 y = 34

4 x^{2} + 4 y^{2} = 9

What is x^2+(y+8)^2=400 ?
The solution to x^2+(y+8)^2=400 is Circle with (a,b)=(0,-8),r=20