What is (x-2/5)^2+(y-1/7)^2= 4/9 ?

The solution to (x-2/5)^2+(y-1/7)^2= 4/9 is Circle with (a,b)=(2/5 , 1/7),r= 2/3

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(x-2/5)^2+(y-1/7)^2= 4/9

(x - \frac{2}{5})^{2} + (y - \frac{1}{7})^{2} = \frac{4}{9}

(a, b) = (\frac{2}{5}, \frac{1}{7}), r = \frac{2}{3}

Solution steps

(x - \frac{2}{5})^{2} + (y - \frac{1}{7})^{2} = \frac{4}{9}

Rewrite

(x - \frac{2}{5})^{2} + (y - \frac{1}{7})^{2} = \frac{4}{9}

in the form of the standard circle equation

(x - \frac{2}{5})^{2} + (y - \frac{1}{7})^{2} = (\frac{2}{3})^{2}

Therefore the circle properties are:

(a, b) = (\frac{2}{5}, \frac{1}{7}), r = \frac{2}{3}

(x - 4)^{2} + (y + 5)^{2} = 4

4 x^{2} + 4 y^{2} = 1156

(x - 3)^{2} + (y - 0)^{2} = 9

2 x^{(2)} + 2 y^{(2)} + 10 x = 2 y + 7

(x + 2)^{2} + (y + 5)^{2} = 16

What is (x-2/5)^2+(y-1/7)^2= 4/9 ?
The solution to (x-2/5)^2+(y-1/7)^2= 4/9 is Circle with (a,b)=(2/5 , 1/7),r= 2/3