What is x^2-16x+y^2-12y=0 ?

The solution to x^2-16x+y^2-12y=0 is Circle with (a,b)=(8,6),r=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-16x+y^2-12y=0

x^{2} - 16 x + y^{2} - 12 y = 0

(a, b) = (8, 6), r = 10

Solution steps

x^{2} - 16 x + y^{2} - 12 y = 0

Rewrite

x^{2} - 16 x + y^{2} - 12 y = 0

in the form of the standard circle equation

(x - 8)^{2} + (y - 6)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (8, 6), r = 10

x^{2} + y^{2} - 18 x + 18 y + 81 = 0

(x - 2)^{2} + (y + 1)^{2} = 4^{2}

2 x^{2} + 2 y^{2} - 4 x - 8 y = 10

3 x^{2} + 3 y^{2} - 1 = 0

x^{2} + y^{2} - 12 x + 10 y + 23 = 0

What is x^2-16x+y^2-12y=0 ?
The solution to x^2-16x+y^2-12y=0 is Circle with (a,b)=(8,6),r=10