What is x^2+y^2-18x+18y+81=0 ?

The solution to x^2+y^2-18x+18y+81=0 is Circle with (a,b)=(9,-9),r=9

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x^2+y^2-18x+18y+81=0

x^{2} + y^{2} - 18 x + 18 y + 81 = 0

(a, b) = (9, - 9), r = 9

Solution steps

x^{2} + y^{2} - 18 x + 18 y + 81 = 0

Rewrite

x^{2} + y^{2} - 18 x + 18 y + 81 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 9))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (9, - 9), r = 9

(x - 2)^{2} + (y + 1)^{2} = 4^{2}

2 x^{2} + 2 y^{2} - 4 x - 8 y = 10

3 x^{2} + 3 y^{2} - 1 = 0

x^{2} + y^{2} - 12 x + 10 y + 23 = 0

x^{2} + y^{2} + 10 x = 11 - 2 y

What is x^2+y^2-18x+18y+81=0 ?
The solution to x^2+y^2-18x+18y+81=0 is Circle with (a,b)=(9,-9),r=9