What is x^{(2)}+y^{(2)}+2x-7=0 ?

The solution to x^{(2)}+y^{(2)}+2x-7=0 is Circle with (a,b)=(-1,0),r=2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{(2)}+y^{(2)}+2x-7=0

x^{(2)} + y^{(2)} + 2 x - 7 = 0

(a, b) = (- 1, 0), r = 22

Solution steps

x^{2} + y^{2} + 2 x - 7 = 0

Rewrite

x^{2} + y^{2} + 2 x - 7 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = (22)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = 22

x^{2} + y^{2} = 2 5^{2}

(x + 3)^{2} + (y - 3)^{2} = 8

(x^{2} + y^{2}) = 58

9 x^{2} + 6 x + 8 + 9 y^{2} - 24 y = 0

x^{2} + (y - 6)^{2} = 16

What is x^{(2)}+y^{(2)}+2x-7=0 ?
The solution to x^{(2)}+y^{(2)}+2x-7=0 is Circle with (a,b)=(-1,0),r=2sqrt(2)