What is (x+y)2=x^2+y^2 ?

The solution to (x+y)2=x^2+y^2 is Circle with (a,b)=(1,1),r=sqrt(2)

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(x+y)2=x^2+y^2

(x + y) 2 = x^{2} + y^{2}

(a, b) = (1, 1), r = 2

Solution steps

(x + y) \cdot 2 = x^{2} + y^{2}

Rewrite

(x + y) 2 = x^{2} + y^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - 1)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (1, 1), r = 2

x^{2} + y^{2} + 3 x - 8 y + 18 = 0

x^{2} + y^{2} - 2 x + 28 y + 181 = 0

4 (x - 4)^{2} + 4 y^{2} = 4

x^{2} + y^{2} + 10 x + 6 y = 10

x^{2} + y^{2} + 4 x + 6 y - 3 = 0

What is (x+y)2=x^2+y^2 ?
The solution to (x+y)2=x^2+y^2 is Circle with (a,b)=(1,1),r=sqrt(2)