What is x^2+y^2-2x+28y+181=0 ?

The solution to x^2+y^2-2x+28y+181=0 is Circle with (a,b)=(1,-14),r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-2x+28y+181=0

x^{2} + y^{2} - 2 x + 28 y + 181 = 0

(a, b) = (1, - 14), r = 4

Solution steps

x^{2} + y^{2} - 2 x + 28 y + 181 = 0

Rewrite

x^{2} + y^{2} - 2 x + 28 y + 181 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 14))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 14), r = 4

4 (x - 4)^{2} + 4 y^{2} = 4

x^{2} + y^{2} + 10 x + 6 y = 10

x^{2} + y^{2} + 4 x + 6 y - 3 = 0

x^{2} + y^{2} + 3 x = 0

x^{2} = - y^{2} + 16

What is x^2+y^2-2x+28y+181=0 ?
The solution to x^2+y^2-2x+28y+181=0 is Circle with (a,b)=(1,-14),r=4