What is x^2+y^2+3x=0 ?

The solution to x^2+y^2+3x=0 is Circle with (a,b)=(-3/2 ,0),r= 3/2

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x^2+y^2+3x=0

x^{2} + y^{2} + 3 x = 0

(a, b) = (- \frac{3}{2}, 0), r = \frac{3}{2}

Solution steps

x^{2} + y^{2} + 3 x = 0

Rewrite

x^{2} + y^{2} + 3 x = 0

in the form of the standard circle equation

(x - (- \frac{3}{2}))^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{2}, 0), r = \frac{3}{2}

x^{2} = - y^{2} + 16

9 = (x + 3)^{2} + (y + 1)^{2}

(x - 1)^{2} + (y + 6)^{2} = 4

x^{2} + y^{2} + 8 x - 6 y + 21 = 0

x^{2} + y^{2} - 2 x + 8 y - 47 = 0

What is x^2+y^2+3x=0 ?
The solution to x^2+y^2+3x=0 is Circle with (a,b)=(-3/2 ,0),r= 3/2