What is x^2+y^2+8x-6y+21=0 ?

The solution to x^2+y^2+8x-6y+21=0 is Circle with (a,b)=(-4,3),r=2

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x^2+y^2+8x-6y+21=0

x^{2} + y^{2} + 8 x - 6 y + 21 = 0

(a, b) = (- 4, 3), r = 2

Solution steps

x^{2} + y^{2} + 8 x - 6 y + 21 = 0

Rewrite

x^{2} + y^{2} + 8 x - 6 y + 21 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 4, 3), r = 2

x^{2} + y^{2} - 2 x + 8 y - 47 = 0

(x - 4)^{2} + (y + 3)^{2} = 25

x^{2} + y^{2} - 6 x - 16 y + 24 = 0

x^{(2)} + y^{(2)} - 4 x - 6 y + 9 = 0

(x - 4)^{2} + (y + 3)^{2} = 16

What is x^2+y^2+8x-6y+21=0 ?
The solution to x^2+y^2+8x-6y+21=0 is Circle with (a,b)=(-4,3),r=2