What is x^2+y^2-22y-5=0 ?

The solution to x^2+y^2-22y-5=0 is Circle with (a,b)=(0,11),r=3sqrt(14)

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x^2+y^2-22y-5=0

x^{2} + y^{2} - 22 y - 5 = 0

(a, b) = (0, 11), r = 314

Solution steps

x^{2} + y^{2} - 22 y - 5 = 0

Rewrite

x^{2} + y^{2} - 22 y - 5 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 11)^{2} = (314)^{2}

Therefore the circle properties are:

(a, b) = (0, 11), r = 314

x^{2} + y^{2} + 6 x + 8 y - 75 = 0

\frac{1}{2} x^{2} + \frac{1}{2} y^{2} = 16

(x - 5)^{2} + y^{2} = 38

(x - 4)^{2} + (y - 2)^{2} = 4

x - y + x^{2} + y^{2} - 1 = 0

What is x^2+y^2-22y-5=0 ?
The solution to x^2+y^2-22y-5=0 is Circle with (a,b)=(0,11),r=3sqrt(14)