What is x^2+y^2-4x+6y=0 ?

The solution to x^2+y^2-4x+6y=0 is Circle with (a,b)=(2,-3),r=sqrt(13)

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x^2+y^2-4x+6y=0

x^{2} + y^{2} - 4 x + 6 y = 0

(a, b) = (2, - 3), r = 13

Solution steps

x^{2} + y^{2} - 4 x + 6 y = 0

Rewrite

x^{2} + y^{2} - 4 x + 6 y = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 13

x^{2} + y^{2} + 28 x + 52 = 0

3 x^{2} + 3 y^{2} - 12 y - 8 = 0

(x - 2)^{2} + (y - 4)^{2} = 4

- x^{2} - 6 x = z^{2} + 2 z + 1

x^{2} + y^{2} + 2 x + 12 y - 27 = 0

What is x^2+y^2-4x+6y=0 ?
The solution to x^2+y^2-4x+6y=0 is Circle with (a,b)=(2,-3),r=sqrt(13)