What is x^2+y^2+2x+12y-27=0 ?

The solution to x^2+y^2+2x+12y-27=0 is Circle with (a,b)=(-1,-6),r=8

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x^2+y^2+2x+12y-27=0

x^{2} + y^{2} + 2 x + 12 y - 27 = 0

(a, b) = (- 1, - 6), r = 8

Solution steps

x^{2} + y^{2} + 2 x + 12 y - 27 = 0

Rewrite

x^{2} + y^{2} + 2 x + 12 y - 27 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 6))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 6), r = 8

4 - x^{2} - y^{2} = 0

x^{2} + y^{2} + 20 x - 6 y = - 108

4 (x + 8)^{2} + 4 (y + 1)^{2} = 16

a^{2} + b^{2} = 1044

(x + 3)^{2} + (y - 2)^{2} = 8

What is x^2+y^2+2x+12y-27=0 ?
The solution to x^2+y^2+2x+12y-27=0 is Circle with (a,b)=(-1,-6),r=8