What is 4(x+8)^2+4(y+1)^2=16 ?

The solution to 4(x+8)^2+4(y+1)^2=16 is Circle with (a,b)=(-8,-1),r=2

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4(x+8)^2+4(y+1)^2=16

4 (x + 8)^{2} + 4 (y + 1)^{2} = 16

(a, b) = (- 8, - 1), r = 2

Solution steps

4 (x + 8)^{2} + 4 (y + 1)^{2} = 16

Rewrite

4 (x + 8)^{2} + 4 (y + 1)^{2} = 16

in the form of the standard circle equation

(x - (- 8))^{2} + (y - (- 1))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 8, - 1), r = 2

a^{2} + b^{2} = 1044

(x + 3)^{2} + (y - 2)^{2} = 8

2 x^{2} + 2 y^{2} = 5

2 x^{2} + 2 y^{2} = 9

(x + 4)^{2} + y^{2} = 9

What is 4(x+8)^2+4(y+1)^2=16 ?
The solution to 4(x+8)^2+4(y+1)^2=16 is Circle with (a,b)=(-8,-1),r=2