What is x^2-10x+25+y^2-8y+16=64 ?

The solution to x^2-10x+25+y^2-8y+16=64 is Circle with (a,b)=(5,4),r=8

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x^2-10x+25+y^2-8y+16=64

x^{2} - 10 x + 25 + y^{2} - 8 y + 16 = 64

(a, b) = (5, 4), r = 8

Solution steps

x^{2} - 10 x + 25 + y^{2} - 8 y + 16 = 64

Rewrite

x^{2} - 10 x + 25 + y^{2} - 8 y + 16 = 64

in the form of the standard circle equation

(x - 5)^{2} + (y - 4)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (5, 4), r = 8

(x - 2)^{2} + (y - 4)^{2} = 25

(x - 2)^{2} + (y - 4)^{2} = 16

(x + 4)^{2} + (y + 1)^{2} = 25

x^{2} + y^{2} - 8 x + 14 y + 40 = 0

(x + 1)^{2} + (y - 2)^{2} = 5^{2}

What is x^2-10x+25+y^2-8y+16=64 ?
The solution to x^2-10x+25+y^2-8y+16=64 is Circle with (a,b)=(5,4),r=8