What is (x+4)^2+(y+1)^2=25 ?

The solution to (x+4)^2+(y+1)^2=25 is Circle with (a,b)=(-4,-1),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+4)^2+(y+1)^2=25

(x + 4)^{2} + (y + 1)^{2} = 25

(a, b) = (- 4, - 1), r = 5

Solution steps

(x + 4)^{2} + (y + 1)^{2} = 25

Rewrite

(x + 4)^{2} + (y + 1)^{2} = 25

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 1))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 1), r = 5

x^{2} + y^{2} - 8 x + 14 y + 40 = 0

(x + 1)^{2} + (y - 2)^{2} = 5^{2}

3 x^{2} + 3 y^{2} - 18 x + 12 y - 36 = 0

(x - 4)^{2} + (y + 1)^{2} = 25

(x - 4)^{2} + (y + 1)^{2} = 16

What is (x+4)^2+(y+1)^2=25 ?
The solution to (x+4)^2+(y+1)^2=25 is Circle with (a,b)=(-4,-1),r=5