What is (x-4)^2+(y+1)^2=25 ?

The solution to (x-4)^2+(y+1)^2=25 is Circle with (a,b)=(4,-1),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-4)^2+(y+1)^2=25

(x - 4)^{2} + (y + 1)^{2} = 25

(a, b) = (4, - 1), r = 5

Solution steps

(x - 4)^{2} + (y + 1)^{2} = 25

Rewrite

(x - 4)^{2} + (y + 1)^{2} = 25

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 1))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (4, - 1), r = 5

(x - 4)^{2} + (y + 1)^{2} = 16

(x + 1)^{2} + (y + 5)^{2} = 25

x^{2} + y^{2} + y = 9

(x + 2)^{2} + (y - 3)^{2} = 5

9 ((x + 6)^{2} + (y - 5)^{2}) = 4 ((x - 3)^{2} + (y + 1)^{2})

What is (x-4)^2+(y+1)^2=25 ?
The solution to (x-4)^2+(y+1)^2=25 is Circle with (a,b)=(4,-1),r=5