What is (x+1)^2+(y+5)^2=25 ?

The solution to (x+1)^2+(y+5)^2=25 is Circle with (a,b)=(-1,-5),r=5

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(x+1)^2+(y+5)^2=25

(x + 1)^{2} + (y + 5)^{2} = 25

(a, b) = (- 1, - 5), r = 5

Solution steps

(x + 1)^{2} + (y + 5)^{2} = 25

Rewrite

(x + 1)^{2} + (y + 5)^{2} = 25

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 5))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 5), r = 5

x^{2} + y^{2} + y = 9

(x + 2)^{2} + (y - 3)^{2} = 5

9 ((x + 6)^{2} + (y - 5)^{2}) = 4 ((x - 3)^{2} + (y + 1)^{2})

3 x^{2} + 18 x + 3 y^{2} = 0

x^{2} + y^{2} + 5 x = 0

What is (x+1)^2+(y+5)^2=25 ?
The solution to (x+1)^2+(y+5)^2=25 is Circle with (a,b)=(-1,-5),r=5