What is (x-13.4)^2+(y+2.6)^2=100 ?

The solution to (x-13.4)^2+(y+2.6)^2=100 is Circle with (a,b)=(13.4,-2.6),r=10

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(x-13.4)^2+(y+2.6)^2=100

(x - 13.4)^{2} + (y + 2.6)^{2} = 100

(a, b) = (13.4, - 2.6), r = 10

Solution steps

(x - 13.4)^{2} + (y + 2.6)^{2} = 100

Rewrite

(x - 13.4)^{2} + (y + 2.6)^{2} = 100

in the form of the standard circle equation

(x - 13.4)^{2} + (y - (- 2.6))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (13.4, - 2.6), r = 10

(x - 3)^{2} + (y + 5)^{2} = 36

x^{2} + y^{2} + 18 x + 4 y - 15 = 0

x^{2} + y^{2} + 2 x + 14 y - 31 = 0

x^{2} + 4 x + y^{2} - 8 y - 5 = 0

x^{2} + y^{2} + 1 x + 5 y - 56 = 0

What is (x-13.4)^2+(y+2.6)^2=100 ?
The solution to (x-13.4)^2+(y+2.6)^2=100 is Circle with (a,b)=(13.4,-2.6),r=10