What is (x-1/3)^2+(y-2)^2=81 ?

The solution to (x-1/3)^2+(y-2)^2=81 is Circle with (a,b)=(1/3 ,2),r=9

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(x-1/3)^2+(y-2)^2=81

(x - \frac{1}{3})^{2} + (y - 2)^{2} = 81

(a, b) = (\frac{1}{3}, 2), r = 9

Solution steps

(x - \frac{1}{3})^{2} + (y - 2)^{2} = 81

Rewrite

(x - \frac{1}{3})^{2} + (y - 2)^{2} = 81

in the form of the standard circle equation

(x - \frac{1}{3})^{2} + (y - 2)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{3}, 2), r = 9

x^{2} + y^{2} - 3 y - 4 = 0

x^{2} + y^{2} + 9 x - 4 y - 2 = 0

3 x^{2} + 30 x + 3 y^{2} + 6 y + 51 = 0

x^{2} + y^{2} = \frac{x}{9} - \frac{y}{7} - \frac{1}{324}

x^{2} + y^{2} - 2 x + 10 y + 22 = 0

What is (x-1/3)^2+(y-2)^2=81 ?
The solution to (x-1/3)^2+(y-2)^2=81 is Circle with (a,b)=(1/3 ,2),r=9