What is x^2+y^2= x/9-y/7-1/324 ?

The solution to x^2+y^2= x/9-y/7-1/324 is Circle with (a,b)=(1/18 ,-1/14),r= 1/14

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x^2+y^2= x/9-y/7-1/324

x^{2} + y^{2} = \frac{x}{9} - \frac{y}{7} - \frac{1}{324}

(a, b) = (\frac{1}{18}, - \frac{1}{14}), r = \frac{1}{14}

Solution steps

x^{2} + y^{2} = \frac{x}{9} - \frac{y}{7} - \frac{1}{324}

Rewrite

x^{2} + y^{2} = \frac{x}{9} - \frac{y}{7} - \frac{1}{324}

in the form of the standard circle equation

(x - \frac{1}{18})^{2} + (y - (- \frac{1}{14}))^{2} = (\frac{1}{14})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{18}, - \frac{1}{14}), r = \frac{1}{14}

x^{2} + y^{2} - 2 x + 10 y + 22 = 0

(x - 4)^{2} + (y + 2)^{2} = 36

(x - 4)^{2} + (y + 2)^{2} = 25

2 x^{2} + 2 y^{2} + 4 x + 16 y + 2 = 0

x^{2} - 4 x + y^{2} + 10 y = 25

What is x^2+y^2= x/9-y/7-1/324 ?
The solution to x^2+y^2= x/9-y/7-1/324 is Circle with (a,b)=(1/18 ,-1/14),r= 1/14