What is (x-4)^2+(y+2)^2=25 ?

The solution to (x-4)^2+(y+2)^2=25 is Circle with (a,b)=(4,-2),r=5

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(x-4)^2+(y+2)^2=25

(x - 4)^{2} + (y + 2)^{2} = 25

(a, b) = (4, - 2), r = 5

Solution steps

(x - 4)^{2} + (y + 2)^{2} = 25

Rewrite

(x - 4)^{2} + (y + 2)^{2} = 25

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (4, - 2), r = 5

2 x^{2} + 2 y^{2} + 4 x + 16 y + 2 = 0

x^{2} - 4 x + y^{2} + 10 y = 25

(x - 3)^{2} + (y + 2)^{2} = 6

x^{2} + y^{2} = 2023

x^{2} + y^{2} - 10 x - 2 y + 1 = 0

What is (x-4)^2+(y+2)^2=25 ?
The solution to (x-4)^2+(y+2)^2=25 is Circle with (a,b)=(4,-2),r=5