What is x^2-4x+y^2+10y=25 ?

The solution to x^2-4x+y^2+10y=25 is Circle with (a,b)=(2,-5),r=3sqrt(6)

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x^2-4x+y^2+10y=25

x^{2} - 4 x + y^{2} + 10 y = 25

(a, b) = (2, - 5), r = 36

Solution steps

x^{2} - 4 x + y^{2} + 10 y = 25

Rewrite

x^{2} - 4 x + y^{2} + 10 y = 25

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 5))^{2} = (36)^{2}

Therefore the circle properties are:

(a, b) = (2, - 5), r = 36

(x - 3)^{2} + (y + 2)^{2} = 6

x^{2} + y^{2} = 2023

x^{2} + y^{2} - 10 x - 2 y + 1 = 0

x^{2} + y^{2} - 2 x + 4 y + 2 = 0

(x - 15)^{2} + (y + 20)^{2} = 81

What is x^2-4x+y^2+10y=25 ?
The solution to x^2-4x+y^2+10y=25 is Circle with (a,b)=(2,-5),r=3sqrt(6)