What is (x-15)^2+(y+20)^2=81 ?

The solution to (x-15)^2+(y+20)^2=81 is Circle with (a,b)=(15,-20),r=9

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(x-15)^2+(y+20)^2=81

(x - 15)^{2} + (y + 20)^{2} = 81

(a, b) = (15, - 20), r = 9

Solution steps

(x - 15)^{2} + (y + 20)^{2} = 81

Rewrite

(x - 15)^{2} + (y + 20)^{2} = 81

in the form of the standard circle equation

(x - 15)^{2} + (y - (- 20))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (15, - 20), r = 9

2 x^{2} + 6 x + 2 y^{2} - 8 y = \frac{11}{2}

x^{2} + y^{2} - 22 x - 12 y + 150 = 0

x^{2} + y^{2} + 4 x - 6 y + 2 = 0

x^{2} + 8 y + y^{2} + 7 = 0

(x - 1)^{2} + (y - 4)^{2} = 4

What is (x-15)^2+(y+20)^2=81 ?
The solution to (x-15)^2+(y+20)^2=81 is Circle with (a,b)=(15,-20),r=9