What is (x-2)^2+(y-1)^2=49 ?

The solution to (x-2)^2+(y-1)^2=49 is Circle with (a,b)=(2,1),r=7

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(x-2)^2+(y-1)^2=49

(x - 2)^{2} + (y - 1)^{2} = 49

(a, b) = (2, 1), r = 7

Solution steps

(x - 2)^{2} + (y - 1)^{2} = 49

Rewrite

(x - 2)^{2} + (y - 1)^{2} = 49

in the form of the standard circle equation

(x - 2)^{2} + (y - 1)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (2, 1), r = 7

y^{2} + x^{2} \leq 1

x^{2} + y^{2} - 6 x - 8 y - 14 = 0

x^{2} + y^{2} + 10 x + 12 y - 3 = 0

x^{2} + y^{2} - 6 x - 4 y - 7 = 0

y = 9 - x^{2} - y^{2}

What is (x-2)^2+(y-1)^2=49 ?
The solution to (x-2)^2+(y-1)^2=49 is Circle with (a,b)=(2,1),r=7