What is x^2+y^2-6x-4y-7=0 ?

The solution to x^2+y^2-6x-4y-7=0 is Circle with (a,b)=(3,2),r=2sqrt(5)

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x^2+y^2-6x-4y-7=0

x^{2} + y^{2} - 6 x - 4 y - 7 = 0

(a, b) = (3, 2), r = 25

Solution steps

x^{2} + y^{2} - 6 x - 4 y - 7 = 0

Rewrite

x^{2} + y^{2} - 6 x - 4 y - 7 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = (25)^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 25

y = 9 - x^{2} - y^{2}

x^{2} + y^{2} + 8 x - 6 y + 5 = 0

x^{2} - 2 x + y^{2} + 2 y = 102

3. 6^{2} = (x + 0.001)^{2} + (y + 0.3)^{2}

x^{2} + y^{2} \geq 25

What is x^2+y^2-6x-4y-7=0 ?
The solution to x^2+y^2-6x-4y-7=0 is Circle with (a,b)=(3,2),r=2sqrt(5)