What is 3.6^2=(x+0.001)^2+(y+0.3)^2 ?

The solution to 3.6^2=(x+0.001)^2+(y+0.3)^2 is Circle with (a,b)=(-0.001,-0.3),r=3.6

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3.6^2=(x+0.001)^2+(y+0.3)^2

3. 6^{2} = (x + 0.001)^{2} + (y + 0.3)^{2}

(a, b) = (- 0.001, - 0.3), r = 3.6

Solution steps

3. 6^{2} = (x + 0.001)^{2} + (y + 0.3)^{2}

Rewrite

3. 6^{2} = (x + 0.001)^{2} + (y + 0.3)^{2}

in the form of the standard circle equation

(x - (- 0.001))^{2} + (y - (- 0.3))^{2} = 3. 6^{2}

Therefore the circle properties are:

(a, b) = (- 0.001, - 0.3), r = 3.6

x^{2} + y^{2} \geq 25

(x - 512)^{2} + y^{2} = 256

x^{2} + y^{2} - x - 6 y + \frac{1}{4} = 0

x^{2} + y^{2} + 6 x - 8 y + 21 = 0

2 5^{2} = a^{2} + b^{2}

What is 3.6^2=(x+0.001)^2+(y+0.3)^2 ?
The solution to 3.6^2=(x+0.001)^2+(y+0.3)^2 is Circle with (a,b)=(-0.001,-0.3),r=3.6