What is (x-(-2))^2+(y-(-5))^2=12^2 ?

The solution to (x-(-2))^2+(y-(-5))^2=12^2 is Circle with (a,b)=(-2,-5),r=12

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(x-(-2))^2+(y-(-5))^2=12^2

(x - (- 2))^{2} + (y - (- 5))^{2} = 1 2^{2}

(a, b) = (- 2, - 5), r = 12

Solution steps

(x - (- 2))^{2} + (y - (- 5))^{2} = 1 2^{2}

Rewrite

(x - (- 2))^{2} + (y - (- 5))^{2} = 1 2^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 5))^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 5), r = 12

x^{2} + y^{2} + 2 x + 4 y + 4 = 0

x^{2} + y^{2} + 4 x + 12 y + 36 = 0

5 x^{2} + 5 y^{2} + 40 x - 10 y + 55 = 0

3 (x + 5)^{2} + 3 (y + 2)^{2} = 27

1 - x^{2} = y^{2}

What is (x-(-2))^2+(y-(-5))^2=12^2 ?
The solution to (x-(-2))^2+(y-(-5))^2=12^2 is Circle with (a,b)=(-2,-5),r=12