What is x^2+14x+y^2+10y=-62 ?

The solution to x^2+14x+y^2+10y=-62 is Circle with (a,b)=(-7,-5),r=2sqrt(3)

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x^2+14x+y^2+10y=-62

x^{2} + 14 x + y^{2} + 10 y = - 62

(a, b) = (- 7, - 5), r = 23

Solution steps

x^{2} + 14 x + y^{2} + 10 y = - 62

Rewrite

x^{2} + 14 x + y^{2} + 10 y = - 62

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 5))^{2} = (23)^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 5), r = 23

(x + 6)^{2} + (y - 2)^{2} = 4

(x - 5)^{2} + (y - 1)^{2} = 49

(x - 1)^{2} + (y + 5)^{2} = 25

x^{2} + y^{2} - \frac{12}{11} x - \frac{84}{11} y - \frac{640}{11} = 0

x^{2} + 8 x + y^{2} + 2 y + 13 = 0

What is x^2+14x+y^2+10y=-62 ?
The solution to x^2+14x+y^2+10y=-62 is Circle with (a,b)=(-7,-5),r=2sqrt(3)