What is x^2+y^2+6x-8y=3 ?

The solution to x^2+y^2+6x-8y=3 is Circle with (a,b)=(-3,4),r=2sqrt(7)

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x^2+y^2+6x-8y=3

x^{2} + y^{2} + 6 x - 8 y = 3

(a, b) = (- 3, 4), r = 27

Solution steps

x^{2} + y^{2} + 6 x - 8 y = 3

Rewrite

x^{2} + y^{2} + 6 x - 8 y = 3

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = (27)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 27

x^{2} + y^{2} - 12 x - 4 y + 39 = 0

x^{2} + y^{2} - 10 x - 12 y - 6 = 0

(x + 18.5)^{2} + (y - 3.1)^{2} = 71

(x + 2)^{2} + (y + 2)^{2} = 3

(x + 3) (x + 3) + (y + 2) (y + 2) = 16

What is x^2+y^2+6x-8y=3 ?
The solution to x^2+y^2+6x-8y=3 is Circle with (a,b)=(-3,4),r=2sqrt(7)