What is x^2+y^2=25(3.4) ?

The solution to x^2+y^2=25(3.4) is Circle with (a,b)=(0,0),r=9.21954…

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x^2+y^2=25(3.4)

x^{2} + y^{2} = 25 (3.4)

(a, b) = (0, 0), r = 9.21954 \dots

Solution steps

x^{2} + y^{2} = 25 \cdot 3.4

Rewrite

x^{2} + y^{2} = 253.4

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 9.21954 \dots^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 9.21954 \dots

(x + 7)^{2} + (y - 2)^{2} = 81

(x - 12)^{2} + (y + 16)^{2} = 400

(x + 7)^{2} + (y - 2)^{2} = 64

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{4} = 1

x^{2} - 4 y + y^{2} - 21 = 0

What is x^2+y^2=25(3.4) ?
The solution to x^2+y^2=25(3.4) is Circle with (a,b)=(0,0),r=9.21954…