What is x^2+(y-1)^2=16 ?

The solution to x^2+(y-1)^2=16 is Circle with (a,b)=(0,1),r=4

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x^2+(y-1)^2=16

x^{2} + (y - 1)^{2} = 16

(a, b) = (0, 1), r = 4

Solution steps

x^{2} + (y - 1)^{2} = 16

Rewrite

x^{2} + (y - 1)^{2} = 16

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 4

(x^{2} - 10 x + 25) + (y^{2} + 4 y + 4) = 36

x^{2} + y^{2} - 2 x - 2 y = 2

x^{2} + y^{2} - 6 x + 12 y + 41 = 0

(\frac{x - 19}{4})^{2} + (\frac{y - 9}{4})^{2} = 17

x^{2} + y^{2} + 4 x - 8 y + 16 = 0

What is x^2+(y-1)^2=16 ?
The solution to x^2+(y-1)^2=16 is Circle with (a,b)=(0,1),r=4