What is (x+1)^2+(y-2)^2=100 ?

The solution to (x+1)^2+(y-2)^2=100 is Circle with (a,b)=(-1,2),r=10

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(x+1)^2+(y-2)^2=100

(x + 1)^{2} + (y - 2)^{2} = 100

(a, b) = (- 1, 2), r = 10

Solution steps

(x + 1)^{2} + (y - 2)^{2} = 100

Rewrite

(x + 1)^{2} + (y - 2)^{2} = 100

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 2)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 1, 2), r = 10

x^{2} + y^{2} + 6 x - 2 y - 10 = 0

(x - (- 7))^{2} + (y - (- 6))^{2} = 19^{2}

x^{2} + y^{2} - 8 x + 2 y + 4 = 0

(x - 2)^{2} + (y + 1)^{2} = 13

(x - \frac{7}{2})^{2} + (y - 1)^{2} = 4.27

What is (x+1)^2+(y-2)^2=100 ?
The solution to (x+1)^2+(y-2)^2=100 is Circle with (a,b)=(-1,2),r=10