What is x^2+y^2-5x=3 ?

The solution to x^2+y^2-5x=3 is Circle with (a,b)=(5/2 ,0),r=(sqrt(37))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-5x=3

x^{2} + y^{2} - 5 x = 3

(a, b) = (\frac{5}{2}, 0), r = \frac{37}{2}

Solution steps

x^{2} + y^{2} - 5 x = 3

Rewrite

x^{2} + y^{2} - 5 x = 3

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - 0)^{2} = (\frac{37}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, 0), r = \frac{37}{2}

(x - 1 + 23)^{2} + (y - 3)^{2} = 20

x^{2} + y^{2} + 4 x + 2 y - 27 = 0

x^{2} + y^{2} = - 4 x - 3 y

(x - (- 4))^{2} + (y - (9))^{2} = 3^{2}

x^{2} + (y + 4)^{2} = 25

What is x^2+y^2-5x=3 ?
The solution to x^2+y^2-5x=3 is Circle with (a,b)=(5/2 ,0),r=(sqrt(37))/2