What is x-y+x^2+y^2=17 ?

The solution to x-y+x^2+y^2=17 is Circle with (a,b)=(-1/2 , 1/2),r=sqrt(35/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x-y+x^2+y^2=17

x - y + x^{2} + y^{2} = 17

(a, b) = (- \frac{1}{2}, \frac{1}{2}), r = \frac{35}{2}

Solution steps

x - y + x^{2} + y^{2} = 17

Rewrite

x - y + x^{2} + y^{2} = 17

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - \frac{1}{2})^{2} = (\frac{35}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, \frac{1}{2}), r = \frac{35}{2}

x^{2} + y^{2} + x - 4 y - 11 = 0

x^{2} + y^{2} + 2 x + 4 y + \frac{1}{3} > 0

x^{2} + y^{2} - \frac{1}{2} x - \frac{3}{2} y = \frac{71}{16}

(x^{2} - 4 x) + (y^{2} + 2 y) = 31

(x + 9)^{2} + (y + 2)^{2} = 4

What is x-y+x^2+y^2=17 ?
The solution to x-y+x^2+y^2=17 is Circle with (a,b)=(-1/2 , 1/2),r=sqrt(35/2)