What is x^2+2x+y^2-2y=-1 ?

The solution to x^2+2x+y^2-2y=-1 is Circle with (a,b)=(-1,1),r=1

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x^2+2x+y^2-2y=-1

x^{2} + 2 x + y^{2} - 2 y = - 1

(a, b) = (- 1, 1), r = 1

Solution steps

x^{2} + 2 x + y^{2} - 2 y = - 1

Rewrite

x^{2} + 2 x + y^{2} - 2 y = - 1

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 1

x^{2} + y^{2} + 10 x - 23 = 0

(X - 4)^{2} + (Y + 9)^{2} = 2

(x - 4)^{2} + (y - 4)^{2} = 3^{2}

x^{(2)} + y^{(2)} - 6 x + 2 y - 6 = 0

2 x^{2} + 2 y^{2} + 14 x - 10 y + 35 = 0

What is x^2+2x+y^2-2y=-1 ?
The solution to x^2+2x+y^2-2y=-1 is Circle with (a,b)=(-1,1),r=1