What is (X-4)^2+(Y+9)^2=sqrt(2) ?

The solution to (X-4)^2+(Y+9)^2=sqrt(2) is Circle with (a,b)=(4,-9),r=sqrt(\sqrt{2)}

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(X-4)^2+(Y+9)^2=sqrt(2)

(X - 4)^{2} + (Y + 9)^{2} = 2

(a, b) = (4, - 9), r = 2

Solution steps

(X - 4)^{2} + (Y + 9)^{2} = 2

Rewrite

(X - 4)^{2} + (Y + 9)^{2} = 2

in the form of the standard circle equation

(X - 4)^{2} + (Y - (- 9))^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (4, - 9), r = 2

(x - 4)^{2} + (y - 4)^{2} = 3^{2}

x^{(2)} + y^{(2)} - 6 x + 2 y - 6 = 0

2 x^{2} + 2 y^{2} + 14 x - 10 y + 35 = 0

x^{2} + y^{2} + x + 6 y - 55 = 0

x^{2} + y^{2} - 8 x - 6 y - 19 = 0

What is (X-4)^2+(Y+9)^2=sqrt(2) ?
The solution to (X-4)^2+(Y+9)^2=sqrt(2) is Circle with (a,b)=(4,-9),r=sqrt(\sqrt{2)}