What is x^2+y^2-8x-6y-19=0 ?

The solution to x^2+y^2-8x-6y-19=0 is Circle with (a,b)=(4,3),r=2sqrt(11)

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x^2+y^2-8x-6y-19=0

x^{2} + y^{2} - 8 x - 6 y - 19 = 0

(a, b) = (4, 3), r = 211

Solution steps

x^{2} + y^{2} - 8 x - 6 y - 19 = 0

Rewrite

x^{2} + y^{2} - 8 x - 6 y - 19 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - 3)^{2} = (211)^{2}

Therefore the circle properties are:

(a, b) = (4, 3), r = 211

(x - \frac{23}{5})^{2} + (y + \frac{2}{5})^{2} = \frac{373}{25}

(x + 3)^{2} + (y + 2)^{2} = 45

(x - 2)^{(2)} + (y - 3)^{(2)} = 7

(a + b) + (a - b) = a^{2} + b^{2}

(x + 3)^{2} + (y + 2)^{2} = 36

What is x^2+y^2-8x-6y-19=0 ?
The solution to x^2+y^2-8x-6y-19=0 is Circle with (a,b)=(4,3),r=2sqrt(11)