What is (x-23/5)^2+(y+2/5)^2= 373/25 ?

The solution to (x-23/5)^2+(y+2/5)^2= 373/25 is Circle with (a,b)=(23/5 ,-2/5),r=sqrt(373/25)

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(x-23/5)^2+(y+2/5)^2= 373/25

(x - \frac{23}{5})^{2} + (y + \frac{2}{5})^{2} = \frac{373}{25}

(a, b) = (\frac{23}{5}, - \frac{2}{5}), r = \frac{373}{25}

Solution steps

(x - \frac{23}{5})^{2} + (y + \frac{2}{5})^{2} = \frac{373}{25}

Rewrite

(x - \frac{23}{5})^{2} + (y + \frac{2}{5})^{2} = \frac{373}{25}

in the form of the standard circle equation

(x - \frac{23}{5})^{2} + (y - (- \frac{2}{5}))^{2} = (\frac{373}{25})^{2}

Therefore the circle properties are:

(a, b) = (\frac{23}{5}, - \frac{2}{5}), r = \frac{373}{25}

(x + 3)^{2} + (y + 2)^{2} = 45

(x - 2)^{(2)} + (y - 3)^{(2)} = 7

(a + b) + (a - b) = a^{2} + b^{2}

(x + 3)^{2} + (y + 2)^{2} = 36

x^{2} + y^{2} + 10 x - 12 y + 12 = 0

What is (x-23/5)^2+(y+2/5)^2= 373/25 ?
The solution to (x-23/5)^2+(y+2/5)^2= 373/25 is Circle with (a,b)=(23/5 ,-2/5),r=sqrt(373/25)