What is 2x^2+2y^2+8x-8y=34 ?

The solution to 2x^2+2y^2+8x-8y=34 is Circle with (a,b)=(-2,2),r=5

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2x^2+2y^2+8x-8y=34

2 x^{2} + 2 y^{2} + 8 x - 8 y = 34

(a, b) = (- 2, 2), r = 5

Solution steps

2 x^{2} + 2 y^{2} + 8 x - 8 y = 34

Rewrite

2 x^{2} + 2 y^{2} + 8 x - 8 y = 34

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 2), r = 5

x^{2} + y^{2} - 4 - 2 x - 4 y = 0

(x - 2)^{2} + (y + 3)^{2} = 4^{2}

x^{2} + y^{2} - 6 y = 7

x^{2} + y^{2} = 49 + (- 2)

2 x^{2} - 6 x + 2 y^{2} = 0

What is 2x^2+2y^2+8x-8y=34 ?
The solution to 2x^2+2y^2+8x-8y=34 is Circle with (a,b)=(-2,2),r=5