What is 2x^2-6x+2y^2=0 ?

The solution to 2x^2-6x+2y^2=0 is Circle with (a,b)=(3/2 ,0),r= 3/2

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2x^2-6x+2y^2=0

2 x^{2} - 6 x + 2 y^{2} = 0

(a, b) = (\frac{3}{2}, 0), r = \frac{3}{2}

Solution steps

2 x^{2} - 6 x + 2 y^{2} = 0

Rewrite

2 x^{2} - 6 x + 2 y^{2} = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, 0), r = \frac{3}{2}

(x - 3)^{2} + (y - 1)^{2} = 2

(x^{2} - 4 x) + (y^{2} - 6 y) = 23

(x + 2)^{(2)} + (y + 5)^{(2)} = 144

x^{2} + 4 x + 2^{2} + y^{2} + 8 y + 4^{2} - 5 = 20

x^{2} + y^{2} - 5 x - 3 y = 0

What is 2x^2-6x+2y^2=0 ?
The solution to 2x^2-6x+2y^2=0 is Circle with (a,b)=(3/2 ,0),r= 3/2