What is (x^2-4x)+(y^2-6y)=23 ?

The solution to (x^2-4x)+(y^2-6y)=23 is Circle with (a,b)=(2,3),r=6

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(x^2-4x)+(y^2-6y)=23

(x^{2} - 4 x) + (y^{2} - 6 y) = 23

(a, b) = (2, 3), r = 6

Solution steps

x^{2} - 4 x + (y^{2} - 6 y) = 23

Rewrite

x^{2} - 4 x + (y^{2} - 6 y) = 23

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 6

(x + 2)^{(2)} + (y + 5)^{(2)} = 144

x^{2} + 4 x + 2^{2} + y^{2} + 8 y + 4^{2} - 5 = 20

x^{2} + y^{2} - 5 x - 3 y = 0

9 x^{2} + 72 x + 9 y^{2} - 12 y + 103 = 0

(x + 3)^{2} + (y - 2)^{2} = 64

What is (x^2-4x)+(y^2-6y)=23 ?
The solution to (x^2-4x)+(y^2-6y)=23 is Circle with (a,b)=(2,3),r=6