What is x^2+y^2=3x+y-2 ?

The solution to x^2+y^2=3x+y-2 is Circle with (a,b)=(3/2 , 1/2),r=sqrt(1/2)

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x^2+y^2=3x+y-2

x^{2} + y^{2} = 3 x + y - 2

(a, b) = (\frac{3}{2}, \frac{1}{2}), r = \frac{1}{2}

Solution steps

x^{2} + y^{2} = 3 x + y - 2

Rewrite

x^{2} + y^{2} = 3 x + y - 2

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - \frac{1}{2})^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, \frac{1}{2}), r = \frac{1}{2}

x^{2} + (y - 4)^{2} = 64

x^{2} - x + y^{2} + 3 y - \frac{6}{4} = 0

x^{2} + y^{2} - 16 x + 4 y + 43 = 0

5 x^{2} + 5 y^{2} - 9 x - 19 y - 26 = 0

x^{2} + y^{2} + 6 x - 13 y = 0

What is x^2+y^2=3x+y-2 ?
The solution to x^2+y^2=3x+y-2 is Circle with (a,b)=(3/2 , 1/2),r=sqrt(1/2)