What is x^2+y^2+6x-13y=0 ?

The solution to x^2+y^2+6x-13y=0 is Circle with (a,b)=(-3, 13/2),r=(sqrt(205))/2

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x^2+y^2+6x-13y=0

x^{2} + y^{2} + 6 x - 13 y = 0

(a, b) = (- 3, \frac{13}{2}), r = \frac{205}{2}

Solution steps

x^{2} + y^{2} + 6 x - 13 y = 0

Rewrite

x^{2} + y^{2} + 6 x - 13 y = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - \frac{13}{2})^{2} = (\frac{205}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, \frac{13}{2}), r = \frac{205}{2}

x^{2} + y^{2} - 12 x + 27 = 0

x^{2} + y^{2} + 6 x + 4 y - 32 = 0

x^{2} + y^{2} + 8 x - 6 y + 3 = 0

2 x^{2} + 2 y^{2} - 16 x + 24 y - 96 = 0

(x + 8)^{2} + (y + 13)^{2} = 58

What is x^2+y^2+6x-13y=0 ?
The solution to x^2+y^2+6x-13y=0 is Circle with (a,b)=(-3, 13/2),r=(sqrt(205))/2